If a cooling water system blows down 15,000 gallons per day and the product contains 14% sodium molybdate, what is your daily feed rate in pounds for 5 ppm of Mo?

To determine the daily feed rate of sodium molybdate required to achieve a concentration of 5 ppm of molybdenum (Mo) in the cooling water system, it's essential to understand the calculations involved.

First, we need to calculate the total mass of molybdenum desired in the system. The system blows down 15,000 gallons of water per day, and 5 ppm means that for every one million parts of water, five parts are molybdenum.

Since there are approximately 8.34 pounds of water per gallon, the total weight of the water being blown down is:

15,000 gallons x 8.34 pounds/gallon = 125,100 pounds of water.

Now, to find the desired weight of molybdenum in 5 ppm, you calculate:

5 ppm = 5 parts per million = 5 mg of Mo per liter of water.

To convert this to pounds, we recognize that there are approximately 3.78541 liters in a gallon, thus:

In 15,000 gallons, the number of liters is 15,000 gallons x 3.78541 liters/gallon = 56,781.15 liters.

Now, calculate the total mass of mol