If a pump operates only 50% of the time, what should be the delivery in ml/min for a desired chemical feed rate of 15 gallons per day?

To determine the appropriate delivery in ml/min for a chemical feed rate of 15 gallons per day when a pump operates only 50% of the time, it's essential to first convert the desired feed rate from gallons to milliliters.

One gallon is equivalent to approximately 3,785.41 milliliters. Therefore, 15 gallons can be calculated as:

15 gallons/day × 3,785.41 ml/gallon = 56,781.15 ml/day.

Given that the pump operates only half of the time, we need to account for that by halving the total delivery required. Thus:

56,781.15 ml/day ÷ 2 = 28,390.58 ml/day.

Next, we convert this daily rate to a per minute basis. There are 1,440 minutes in a day (24 hours × 60 minutes). Consequently, the required delivery in ml/min can be computed as follows:

28,390.58 ml/day ÷ 1,440 min/day ≈ 19.7 ml/min.

This value represents the delivery rate needed while the pump is operational. However, since the question relates to a portion of time (50% operation), you would set the target delivery